Question

1. For the travelling harmonic motion wave = 2.0 cos 2pi( 10 t 0.0080x + 0.35).What is the phase difference between oscillatory motion at two points separated by a distance of

i. 4m

ii. 0.5m?

Answer 1

The given equation is $$\begin{gathered} y=2\cos (10t-0.0080x+0.35) \\ compairingitwiths\tan dardequationofdisplacement \\ Y=a\cos \left[2\pi \left(\frac{t}{T}-\frac{x}{\lambda }\right)+\varphi \right]weget \\ \frac{2\pi }{\lambda }=0.0080 \\ \lambda =\frac{2\pi }{0.0080}cm=\frac{2\pi }{0.80}mphasedifference∆\phi =\frac{2\pi }{\lambda }\times pathdifference(∆x)i)0.80\times 4=3.20radii)0.80\times 0.5=0.40rad \end{gathered}$$