10 ml of a solution of HCL is found to be completely neutralized by 5 ml of given KOH solution . if 15 ml of same solution of HCL is used, then the vol of same solution of KOH solution is
1. 10 ml 2.7.5 ml 3.20 ml 4. 15 ml

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Solution

10 mL of HCl solution is neutralised by = 5 mL of KOH solution
1 mL of HCl solution is neutralised by = $\frac{5}{10} m L$ of KOH solution

15 mL of HCl solution is neutralised by = $\frac{5}{10} \times 15$ = 7.5 mL solution of KOH is required

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Similar questions

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Q. Question 3
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10 ml of a solution of HCL is found to be completely neutralized by 5 ml of given KOH solution . if 15 ml of same solution of HCL is used, then the vol of same solution of KOH solution is1. 10 ml 2.7.5 ml 3.20 ml 4. 15 ml

10 mL of HCl solution is neutralised by = 5 mL of KOH solution 1 mL of HCl solution is neutralised by = 510 mL of KOH solution 15 mL of HCl solution is neutralised by = 510×15 = 7.5 mL solution of KOH is required

10 ml of a solution of HCL is found to be completely neutralized by 5 ml of given KOH solution . if 15 ml of same solution of HCL is used, then the vol of same solution of KOH solution is
1. 10 ml 2.7.5 ml 3.20 ml 4. 15 ml

10 mL of HCl solution is neutralised by = 5 mL of KOH solution
1 mL of HCl solution is neutralised by = $\frac{5}{10} m L$ of KOH solution

15 mL of HCl solution is neutralised by = $\frac{5}{10} \times 15$ = 7.5 mL solution of KOH is required