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Byju's Answer
Standard XII
Mathematics
Distance Formula
P 1,1,1 and ...
Question
P
(
1
,
1
,
1
)
and
Q
(
λ
,
λ
,
λ
)
are two points in the space such that
P
Q
=
√
27
, then the value(s) of
λ
can be
A
−
4
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B
−
2
,
4
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C
2
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D
4
,
3
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Solution
The correct option is
B
−
2
,
4
The square of the distance between the
2
points is
3
×
(
λ
−
1
)
2
This has to be equal to
27
.
Hence,
λ
−
1
=
3
,
−
3
λ
=
−
2
,
4
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0
Similar questions
Q.
P
(
1
,
1
,
1
)
and
Q
(
λ
,
λ
,
λ
)
are two points in the space such that
P
Q
=
√
27
,
the value of
λ
can be
Q.
P
(
−
1
,
−
1
,
−
1
)
and
Q
(
λ
,
λ
,
λ
)
are two points in the space such that
P
Q
=
√
48
, then value(s) of
λ
can be
Q.
If
λ
1
and
λ
2
are the two values of
λ
such that the roots
α
and
β
of the quadratic equation,
λ
(
x
2
−
x
)
+
x
+
5
=
0
satisfy
α
β
+
β
α
+
4
5
=
0
, then
λ
1
λ
2
2
+
λ
2
λ
2
1
=
0
is equal to:
Q.
If
A
,
B
,
C
,
D
be
4
distinct points in space such that
−
−
→
A
B
is not perpendicular to
−
−
→
C
D
and satisfies
−
−
→
A
B
.
−
−
→
C
D
=
1
λ
[
¯
¯¯¯¯¯¯¯
¯
A
D
2
+
¯
¯¯¯¯¯¯
¯
B
C
2
−
¯
¯¯¯¯¯¯
¯
A
C
2
−
¯
¯¯¯¯¯¯¯
¯
B
D
2
]
,
then the value of
λ
is
Q.
Find the value of
λ
such that points
P
(
1
,
2
)
,
Q
(
−
2
,
3
)
and
R
(
λ
+
1
,
λ
)
are not forming a triangle?
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