(119)²+(119)(111)+(111)_²/(119)³-(111) =?

Open in App

Solution

$\frac{{(119)}^{2} + (119) (111) + {(111)}^{3}}{{(119)}^{3} - {(111)}^{3}} = \frac{{(119)}^{2} + (119) (111) + {(111)}^{3}}{(119 - 111) [{(119)}^{2} + (119) (111) + {(111)}^{3}]} [as, a^{3} - b^{3} = (a - b) (a^{2} + b^{2} + ab)] = \frac{1}{119 - 111} = \frac{1}{8}$

Suggest Corrections

Similar questions

\frac{(119)^{2} + (119) (111) + (111)^{2}}{(119)^{3} - (111)^{3}}

119^{2} - 111^{2}

119^{2} - 111^{2}

119² - 111² is:

p

\sqrt{p}

a, b

a^{2} - b^{2}

119^{2} - 111^{2}

Join BYJU'S Learning Program