Equation of Tangent at a Point (x,y) in Terms of f'(x)
P2, 2 and Q...
Question
P(2,2) and Q(12,−1) are two points on the parabola y2=2x. The coordinates of the point R on the parabola, where tangent to the curve is parallel to the chord PQ is
A
(54,√52)
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B
(2,−1)
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C
(18,12)
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D
none of these
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Solution
The correct option is C(18,12)
Let point (2t2,2t) lies on curve y2=2x
Then slope is dydx=22y=12t
And this slope is equal to the the slope of line PQ=−1−212−2=2