$(p^{2} + 5 p + 4) \div (p + 1)$

p + 4

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

p

No worries! We‘ve got your back. Try BYJU‘S free classes today!

p - 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $p + 4$
Let us first factorize the numerator of the given division $\frac{p^{2} + 5 p + 4}{p + 1}$ as follows:

$p^{2} + 5 p + 4 = p^{2} + p + 4 p + 4 = p (p + 1) + 4 (p + 1) = (p + 4) (p + 1)$

Since we have to divide $\frac{p^{2} + 5 p + 4}{p + 1}$ , therefore, we will divide $\frac{(p + 1) (p + 4)}{p + 1}$ as shown below:

$\frac{(p + 1) (p + 4)}{p + 1} = p + 4$

Hence, $\frac{p^{2} + 5 p + 4}{p + 1} = p + 4$ .

Suggest Corrections

Similar questions

(p + 8) (p - 3)

(p^{2} + 5 p + 4) \div (p + 1)

4+5(p-1)= 34

Then p =?

p^{2} - p + \frac{1}{4} \div p - \frac{1}{2}

2 p^{4} - 3 p^{3} + p^{2} - 5 p + 7, - 3 p^{4} - 7 p^{3} - 3 p^{2} - p - 12

Join BYJU'S Learning Program