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2 balls are d...

Question

2 balls are dropped from the ground with different heights. 1 ball is dropped 2s after the other but they both strike the ground at the same time if the first ball takes 5s to reach the ground then the difference in initial heights is what?

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Solution

Let initially the first ball be at height h_1,and takes t₁ time to reach the ground = 5 second, and
let initially the second ball be at height h_2,and takes t₂ time to reach the ground = 5-2= 3second
for first Ball For second ball
s = ut+1/2gt²s = ut+1/2gt²
h₁= 0 +1/2 g (5)² h₂ = 0 +1/2g(3)²
h₁ = 25g/2 ...........1> h₂ = 9g/2 .............2>
now the difference in height is h₁- h₂= 25g/2 - 9g/2
= 16g/2 =8g
8 x 9.8 =78.4 meter

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