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Question

2 balls are dropped from the ground with different heights. 1 ball is dropped 2s after the other but they both strike the ground at the same time if the first ball takes 5s to reach the ground then the difference in initial heights is what?

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Solution

Let initially the first ball be at height h​1, and takes t1 time to reach the ground = 5 second, and
let initially the second ball be at height h​2, and takes t2 time to reach the ground = 5-2= 3second
for first Ball For second ball
s = ut+1/2gt2 s = ut+1/2gt2
h1 = 0 +1/2 g (5)2 h2 = 0 +1/2g(3)2
h1 = 25g/2 ...........1> h2 = 9g/2 .............2>
now the difference in height is h1 - h2 = ​ 25g/2 - ​9g/2
= 16g/2 =8g
8 x 9.8 =78.4 meter

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