CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Quantitative Aptitude

Progressions

2 balls are d...

Question

2 balls are dropped from the ground with different heights. 1 ball is dropped 2s after the other but they both strike the ground at the same time if the first ball takes 5s to reach the ground then the difference in initial heights is what?

Open in App

Solution

Let initially the first ball be at height h_1,and takes t₁ time to reach the ground = 5 second, and
let initially the second ball be at height h_2,and takes t₂ time to reach the ground = 5-2= 3second
for first Ball For second ball
s = ut+1/2gt²s = ut+1/2gt²
h₁= 0 +1/2 g (5)² h₂ = 0 +1/2g(3)²
h₁ = 25g/2 ...........1> h₂ = 9g/2 .............2>
now the difference in height is h₁- h₂= 25g/2 - 9g/2
= 16g/2 =8g
8 x 9.8 =78.4 meter

Suggest Corrections

thumbs-up

0

Similar questions

Q. Two balls are dropped to the ground from different heights. One ball is dropped

2 s

after the other but both of them strike the ground simultaneously

5 s

after the first is dropped. The difference in the heights, when they are dropped is (

g = 10 m / s^{2}

)

Q. Two balls are dropped from different heights at different instants. Second ball is dropped

2 s

after the first ball. If both the balls reach the ground simultaneously, after

5 s

of dropping the first ball, then the difference between the initial heights of the two balls will be

(Take g = 9.8 {m/s}^{2})

Q. Two balls are dropped from different heights at different instants. Second ball is dropped

2

sec after the first ball. If both balls reach the ground simultaneously after

5

sec. of dropping the first ball, the difference of initial heights of the two balls will be:

(g = 9.8 m / s^{2})

.

Q. Two balls are dropped from different heights at different instants. Second ball is dropped

2

sec after the first ball. If both balls reach the ground simutlanously after

5

sec of dropping the first ball, the difference of initial heights of the two balls will be:

(g = 9.8 m / s^{2})

Q. A ball is dropped from a height of

10 m

. If the energy of the ball reduces by

40 %

after striking the ground, how high will the ball bounce back after striking the ground for the first time (in meters)?
Take

g = 10 m / s^{2}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Fear of the Dark

QUANTITATIVE APTITUDE

Watch in App

explore_more_icon

Explore more

Other Quantitative Aptitude

Join BYJU'S Learning Program

CrossIcon