Question

2 equal and opposite charges are placed at a certain distance apart and force of attraction between them is F . If 75% charge of one is transfarred to another, then the force between the charges becomes?

Answer 1

Let the charges be q and q initially.

F = Kq²/r²

After the charge transfer,
Q1 = 1.75 q and Q2 = 0.25 q

New force = K(1.75q)(0.25q)/r²
= 0.4375Kq²/r²
= 0.4375F

So, the net force has reduced.