2 lts. of an ideal gas at pressure of 10 atm expands isothermally into vacuum until its total volume is 10 lts.how much heat is absorbed and how much work is done in the expansion?

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Solution

Dear student!
Both are zero, actually , in isothermal expansion at vacuum,
q = -W = P_ext dV
Since, at isothermal expansion, P_ext=0
so, q = -W = 0

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Q. Two litres of an ideal gas at a pressure of 10 atm expands isothermally in vacuum until its total volume is 10 litres. How much heat is absorbed in the expansion?

2 litres of an ideal gas at a pressure of 10atm expands isothermally into vacuum until its total volume is 10 litres. How much work is done? How much heat is absorbed? Consider the same expansion but this time the constant external pressure of 1 ATM?

2 L

of an ideal gas at a pressure of

10

atm expands isothermally into a vacuum until its total volume is

10 L

. How much work is done in the expansion?

2L of an ideal gas at a pressure of 10 atm expansion isothermally into a vacuum until its total volume is 10L.

(i) How much heat is absorbed and how much work is done in the expansion?

(ii) How much heat is absorbed if this system expands against a constant external pressure of 1 atm?

(iii) How much heat is absorbed if the expansion is conducted reversibly at 298K.

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2 lts. of an ideal gas at pressure of 10 atm expands isothermally into vacuum until its total volume is 10 lts.how much heat is absorbed and how much work is done in the expansion?

Dear student!Both are zero, actually , in isothermal expansion at vacuum, q = -W = Pext dVSince, at isothermal expansion, Pext=0 so, q = -W = 0

Dear student!
Both are zero, actually , in isothermal expansion at vacuum,
q = -W = P_ext dV
Since, at isothermal expansion, P_ext=0
so, q = -W = 0