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Preparation Method of HCl

20 g of C aft...

Question

20 g of C after a no. of steps totally converted into a compound by reacting with some metallic hydroxides.that compound contains all H as H₂O and all C as CO₂. this compound is heated and undergoes decomposition.the mass of compound heated is 300 g . suppose the total loss in weight is 120 g. find the % of CO₂ and H₂O in the compound.

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Solution

Carbon reacts with oxygen to form carbon dioxide which further reacts with metallic hydroxide to form metal carbonate and water.
$C + O_{2} \to C O_{2} 12 g 32 g 44 g$

12g of C forms 44 CO₂
20 g of C will form (44/12) x 20 = 73.33 g CO₂

$C O_{2} + m e t a l h y d r o x i d e \to m e t a l c a r b o n a t e + H_{2} O$ $C O_{2} + m e t a l h y d r o x i d e \to m e t a l c a r b o n a t e + H_{2} O$

Mass of compound (metal carbonate + water) formed = 300 g
When the compound is heated it looses CO₂ and water molecules.
Loss in mass = 120g
Therefore, mass of CO₂ + H₂O = 120 g
Now,
Mass of CO₂ in the compound = 73.33g
So, mass of H₂O in the compound = 120 -73.33 = 46.67g
% of CO₂ = (73.33/300) x 100 = 24.44
% of H₂O = (46.67/300) x 100 = 15.55

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