wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

20 J work is required to stretch a spring through 0.1 m. Find the force constant of the spring. If the spring is further stretched through 0.1m. Calculate work done.

Open in App
Solution

the work requires to stretch a spring is equal to the energy stored in it = 1/2 k x2

where k = spring constant and x = deformation of spring

1/2 * k * (0.1)2 = 20

k = 4000 N/m

If the spring is further stretched through 0.1m then the total displacement becomes equal to 0.2 m

work done = 1/2 k x2 = 1/2 * 4000 * (.2)2 = 80 joules


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Work
SCIENCE
Watch in App
Join BYJU'S Learning Program
CrossIcon