P(2,1) is image of the point Q(4,3) about the line
A
x+y=5
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B
x−y=1
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C
3x+y=5
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D
−x+2y=0
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Solution
The correct option is Ax+y=5 Mid point of line PQ is R=(2+42,1+32)=(3,2) slope of PQ=3−14−2=1⇒ slope of line about which image is taken =−1 . ⇒ Line about which image is taken - (y−2)=−1(x−3)y−2=−x+3⇒y+x=5