225 cm³of hydrogen at S.T.P is heated such that its pressure is 810 mm of mercury at a temperature of 97 ^oC. Find the volume of gas

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Solution

At STP 22400 mL is occupied by 1 mole of a gas
Therefore, number of moles of hydrogen gas in 225 ml ( 225 cm³) = (1/22400) $\times$ 225
= 0.01
Now,
760 mm Hg = 1 atm
810 mm Hg = 1.065 atm
97 degree Celsius = 273 + 97 = 370 K

Applying,
PV = nRT
V = (0.01 $\times$ 0.0821 $\times$ 370) / 1.065
= 0.2852 L
= 285.2 mL

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225 cm3 of hydrogen at S.T.P is heated such that its pressure is 810 mm of mercury at a temperature of 97 oC. Find the volume of gas

At STP 22400 mL is occupied by 1 mole of a gas Therefore, number of moles of hydrogen gas in 225 ml ( 225 cm3) = (1/22400) × 225 = 0.01 Now, 760 mm Hg = 1 atm 810 mm Hg = 1.065 atm 97 degree Celsius = 273 + 97 = 370 K Applying, PV = nRT V = (0.01 × 0.0821× 370) / 1.065 = 0.2852 L = 285.2 mL

225 cm³of hydrogen at S.T.P is heated such that its pressure is 810 mm of mercury at a temperature of 97 ^oC. Find the volume of gas