Question

23.The M.I. of a uniform disc of mass Mradius R about an axis which is tangential to the circumference of the disc parallel to its diameter is

Answer 1

$$\begin{gathered} Momentofinertiaofthediscaboutthediamteris\frac{m{r}^2}{4} \\ {I}_d=\frac{m{r}^2}{4} \\ accordingtotheparallelaxistheorm \\ momentofinertiaaboutthe\tan gentisgivenby: \\ I=I_{\mathit{d}}\mathit{}\mathit{+}\mathit{}m{r}^{\mathit{2}} \\ I\mathit{}\mathit{=}\mathit{}\frac{\mathit{m}{\mathit{r}}^{\mathit{2}}}{\mathit{4}}\mathit{+}m{r}^{\mathit{2}} \\ I\mathit{}\mathit{=}\mathit{}\frac{\mathit{5}\mathit{m}{\mathit{r}}^{\mathit{2}}}{\mathit{4}} \end{gathered}$$