25 waves pass through a point in 5s. If the distance between one crest and the adjacent trough is 0.05m , calculate
(a) the frequency
(b)the wavelength
(c)wave velocity
Frequency is equal to the numbers of wave passing through a point in one second.
f = 25/5 = 5 Hz
Distance between one crest and the adjacent trough is 0.05 m
wavelength (λ) is equal to = 0.05 x 2 = 0.1 m
From the relation,
V= f x λ = 5 x 0.1 = 0.5 m/s