When 5 moles of A and 6 moles of B are mixed together
(a) Which one is limtting reagent?
(b)Calculate the amount(no. of moles) of 'C' formed.
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Solution
1) The reactant which produces lesser no. of moles of product is limiting reagent.
2A + 4B 3C + 4D
i) 2 moles of A produces 3 moles of C and 4 moles of D i.e., 7 moles of gases are produced by 2 moles of A.
1 mole of A produces 7/2 moles of C and D
5 moles of A produces 5 (7/2) =35/2= 17.50 moles of C and D
ii) 4 moles of B produces 3 moles of C and 4 moles of D i.e., 7 moles of gases are produced by 4 moles of B.
1 mole of B produces 7/4 moles of C and D
6 moles of B produces 6 x (7/4) = 10.5 moles of C and D are produced
Thus B is a limiting reagent.
2 moles of A and 4 moles of B produces 3 moles of C
1 moles of A and 1 moles of B produces (3/2) + (3/4) moles of C
5 moles of A and 6 moles of C produces 5 (3/2) + 6 (3/4) = 7.5 + 4.5 = 12 moles of C are formed.