Question

34.05mL of phosphorus vapour weighs 0.0625 g at 546 °C and 0.1 barpressure. What is the molar mass of phosphorus?

Answer 1

Given,

p = 0.1 bar

V = 34.05 mL = 34.05 × 10^–3 L = 34.05 × 10^–3 dm³

R = 0.083 bar dm³ K^–1 mol^–1

T = 546°C = (546 + 273) K = 819 K

The number of moles (n) can be calculated using the ideal gas equation as:

Therefore, molar mass of phosphorus = 1247.5 g mol^–1

Hence, the molar mass of phosphorus is 1247.5 g mol^–1.