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Byju's Answer
Standard VIII
Mathematics
Factorisation by Regrouping Terms
p3q3 -pq -p2q...
Question
p
3
q
3
−
p
q
−
p
2
q
2
+
p
4
q
4
can be regrouped and simplified as _______.
A
(
p
q
)
(
1
+
p
q
)
(
1
−
p
q
)
2
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B
(
−
p
q
)
(
1
−
p
q
)
(
1
+
p
q
)
2
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C
(
p
q
)
(
1
+
p
q
)
(
1
+
p
q
)
2
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D
(
−
p
q
)
(
1
−
p
q
)
(
1
+
p
q
)
2
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Solution
The correct option is
D
(
−
p
q
)
(
1
−
p
q
)
(
1
+
p
q
)
2
Given:
p
3
q
3
−
p
q
−
p
2
q
2
+
p
4
q
4
p
3
q
3
−
p
q
−
p
2
q
2
+
p
4
q
4
⇒
p
q
(
p
2
q
2
−
1
)
−
p
2
q
2
(
1
−
p
2
q
2
)
⇒
(
−
p
q
)
(
1
−
p
2
q
2
)
−
p
2
q
2
(
1
−
p
2
q
2
)
⇒
(
1
−
p
2
q
2
)
(
−
1
)
(
p
q
+
p
2
q
2
)
⇒
(
1
−
p
2
q
2
)
(
−
p
q
)
(
1
+
p
q
)
⇒
(
1
+
p
q
)
(
1
−
p
q
)
(
−
p
q
)
(
1
+
p
q
)
⇒
(
−
p
q
)
(
1
−
p
q
)
(
1
+
p
q
)
2
Suggest Corrections
4
Similar questions
Q.
Simplify the polynomial by regrouping method.
5
x
y
3
+
2
x
2
y
2
+
10
x
y
+
4
x
2
Q.
Find the degree of each algebraic expression.
p
q
+
p
2
q
−
p
2
q
2
Q.
Assertion :If
a
x
+
b
y
+
c
z
=
√
a
2
+
b
2
+
c
2
be a plane and
(
x
1
,
y
1
,
z
1
)
and
(
x
2
,
y
2
,
z
2
)
be two points on this plane then
a
(
x
1
−
x
2
)
+
b
(
y
1
−
y
2
)
+
c
(
z
1
−
z
2
)
=
0
Reason: If two vectors
p
1
^
i
+
p
2
^
j
+
p
3
^
k
and
q
1
^
i
+
q
2
^
j
+
p
3
^
k
are orthogonal then
p
1
q
1
+
p
2
q
2
+
p
3
q
3
=
0
Q.
−
2
x
>
22
can be simplified as
Q.
5
−
x
<
6
can be simplified as
.
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