P(4 , 0) & Q(5 , 3) lie on circumference of the circle with centre R(k , 2). Find the value of k.
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If the centre of a circle is (2a, a-7), then the values of 'a', if the circle passes through the point (11,-9) and has diameter 10√2 units will be:
The equation x2+px−q=0 has one root as a square root of the other. If p3+q2=q(1+kp), find the value of k.
If the point A(2,-4) is equidistant from P(3,8) and Q(-10,y), then find the value of y.