Question

$P_4+3NaOH+3H_{2}O\underset{}{\overset{\Delta }{\to }}3Na{H}_2{PO}_2+{PH}_3$
The above reaction is disproportionation reaction. If true enter 1, else enter 0.

Answer 1

$P_4$ ($O.N=0$) disproportionates to $Na{H}_2{PO}_2$ ($O.N$ of $P=+1$) and ${PH}_3$ ($O.N$ of $P=-3$).
Hence, the reaction is disproportionation reaction.