4.8 X 10^-20electrons flow through a circuit in a 20 hours . the magnitude of current flowing in the circuit

(charge on 1 electron= 1.6 X 10^-19 C)

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Solution

Dear Student,
$i = \frac{q}{t} = \frac{n e}{t} i = \frac{4.8 \times 10^{- 20} \times 1.6 \times 10^{- 19}}{20 \times 3600} = 1.06 \times 10^{- 43} A$
Regards

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4.8 X 10-20 electrons flow through a circuit in a 20 hours . the magnitude of current flowing in the circuit (charge on 1 electron= 1.6 X 10-19 C)

Dear Student, i=qt=neti=4.8×10-20×1.6×10-1920×3600=1.06×10-43A Regards

4.8 X 10^-20electrons flow through a circuit in a 20 hours . the magnitude of current flowing in the circuit

(charge on 1 electron= 1.6 X 10^-19 C)

Dear Student,
$i = \frac{q}{t} = \frac{n e}{t} i = \frac{4.8 \times 10^{- 20} \times 1.6 \times 10^{- 19}}{20 \times 3600} = 1.06 \times 10^{- 43} A$
Regards