P4-OH-H2O - H2PO2-PH3Comment on the above reaction-

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Stoichiometric Calculations

P4+OH-+H2O → ...

Question

$P_{4} + O H^{-} + H_{2} O \to H_{2} P O_{2} + P H_{3}$
Comment on the above reaction.

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P_{4})

{P - -}_{4} \to P H_{3} + H_{2} P O_{2}^{-}

P_{4} + O H^{-} + H_{2} O \to H_{2} P O_{2}^{-} + P H_{3}

P_{4} + 3 N a O H + 3 H_{2} O Δ - \to 3 N a H_{2} {P O}_{2} + {P H}_{3}

B + N a O H \to 2 N a_{3} B O_{3} + H_{2}

P_{4} + N a O H + H_{2} O \to N a H_{2} P O_{2} + P H_{3}

S + N a O H \to N a_{2} S_{2} O_{3} + N a_{2} S + H_{2} O

P_{4} + {O H}^{-} \to {P H}_{3} + {H P O}_{2}^{-}

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