5.6 liters of of methane gas (CH4) is ignited in oxygen gas. Calculate the number of moles of CO2 formed

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Solution

CH₄ + 2O₂ â†’ 2H₂O + CO₂
1 mole of methane gives 1 mole of CO₂ gas.Therefore, at STP; 5.6 L of methane will give 5.6 L of CO2 gas.
Volume occupied by 1 mole a gas at STP = 22.4 L
Therefore,
Number of moles in 5.6 L of CO₂ gas = 5.6/22.4
= 0.25 moles.

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5.6 liters of of methane gas (CH4) is ignited in oxygen gas. Calculate the number of moles of CO2 formed

CH4 + 2O2 â†’ 2H2O + CO21 mole of methane gives 1 mole of CO2 gas.Therefore, at STP; 5.6 L of methane will give 5.6 L of CO2 gas.Volume occupied by 1 mole a gas at STP = 22.4 LTherefore,Number of moles in 5.6 L of CO2 gas = 5.6/22.4 = 0.25 moles.

CH₄ + 2O₂ â†’ 2H₂O + CO₂
1 mole of methane gives 1 mole of CO₂ gas.Therefore, at STP; 5.6 L of methane will give 5.6 L of CO2 gas.
Volume occupied by 1 mole a gas at STP = 22.4 L
Therefore,
Number of moles in 5.6 L of CO₂ gas = 5.6/22.4
= 0.25 moles.