Question

5 multiplied by cube root of 1728 + 100 multiplied by four root of 81 minus ( 6 multiplied by square root of 10)raised to 2*

* raised to 2 is only fo the bracket

Answer 1

$$\begin{gathered} 5\sqrt[3]{1728}+100\sqrt[4]{81}-{\left(6\sqrt{10}\right)}^2 \\ =5\times \sqrt[3]{2\times 2\times 2\times 2\times 2\times 2\times 3\times 3\times 3}+100\times \sqrt[4]{3\times 3\times 3\times 3}-360 \\ =5\times 2\times 2\times 3+100\times 3-360 \\ =60+300-360 \\ =360-360 \\ =0 \end{gathered}$$