60 men can complete a work in 250 days. After 200 days, work is stopped for 10 days. How many additional men are required to finish it on time.
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Solution
60 men can finish a work with in 250 days.
1 man can finish the work in 250*60= 15000 days.
60 men worked for 200 days.
So the amount of work done is 200*60=12000 days
So the pending work = 15000-12000=3000 days
The work is stopped for 10 days.
The remaining number of days = 250-200-10=40 days.
The amount fo work done by 60 men in 40 days = 60*40=2400 days
Pending work = 3000-2400= 600 days.
Let x be the additional number of workers required.
Then 40x=600
x= 600/40=15