7/1228/13-7/105/13+2/13

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Solution

$\frac{7}{12} \times \frac{28}{13} - \frac{7}{10} \times \frac{5}{13} + \frac{2}{13} = \frac{196}{156} - \frac{35}{130} + \frac{2}{13} = \frac{980 - 210 + 120}{780} = \frac{890}{780} = \frac{89}{78}$

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Similar questions

Verify the following

(i) $\frac{- 12}{5} + \frac{2}{7} = \frac{2}{7} + \frac{- 12}{5}$

(ii) $\frac{- 5}{8} + \frac{- 9}{13} = \frac{- 9}{13} + \frac{- 5}{8}$

(iii) $3 + \frac{- 7}{12} = \frac{- 7}{12} + 3$

(iv) $\frac{2}{- 7} + \frac{12}{- 35} = \frac{12}{- 35} + \frac{2}{- 7}$

Verify each of the following :

(i) $\frac{3}{7} \times \frac{- 5}{9} = \frac{- 5}{9} \times \frac{3}{7}$

(ii) $\frac{- 8}{7} \times \frac{13}{9} = \frac{13}{9} \times \frac{- 8}{7}$

(iii) $\frac{- 12}{5} \times \frac{7}{- 36} = \frac{7}{- 36} \times \frac{- 12}{5}$

(iv) $- 8 \times \frac{- 13}{12} = \frac{- 13}{12} \times (- 8)$

(\frac{5}{7} \times \frac{12}{13}) \times \frac{7}{18} = \frac{5}{7} (\frac{12}{13} \times \frac{7}{18})

5, 7, 8, 11, 13, 17

3, 7, 7, 12, 13, 10

\frac{3 \times 1^{3}}{1^{2}} + \frac{5 \times (1^{3} + 2^{3})}{1^{2} + 2^{2}} + \frac{7 \times (1^{3} + 2^{3} + 3^{3})}{1^{2} + 2^{2} + 3^{2}} + \dots upto 10 terms

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