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Byju's Answer
Standard XII
Mathematics
Summation by Sigma Method
999*1/7+ 999*...
Question
999*1/7+ 999*2/7+999*3/7+999*4/7 +999*5/7 + 999*6/7 ?
999*x/7 is a single term in each case.
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Solution
If
your
question
is
,
999
×
1
7
+
999
×
2
7
+
999
×
3
7
+
999
×
4
7
+
999
×
5
7
+
999
×
6
7
=
999
1
7
+
2
7
+
3
7
+
4
7
+
5
7
+
6
7
=
999
1
+
2
+
3
+
4
+
5
+
6
7
=
2997
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Similar questions
Q.
999
1
7
+
999
2
7
+
999
3
7
+
999
4
7
+
999
5
7
+
999
6
7
=
?
Q.
What is the value of
999
1
7
+
999
2
7
+
999
3
7
+
999
4
7
+
999
5
7
+
999
6
7
when simplified?
Q.
(
999
999
1000
×
7
)
is equal to
Q.
7, 65, 215, 513, 999, .....
Q.
Find Remainder :
(
27
)
999
7
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