P(a)=0.8;;p(b)=0.5&p,(b/a)=0.4;;;;find p(a intersection b)

Open in App

Solution

P (b/a)=p (b intersection a)/p (a)
p (a intersection b)=p (b/a)p (a)
= 0.4 0.8
= 0.32

Suggest Corrections

Similar questions

P (A) = 0.8, P (B) = 0.5

P (B / A) = 0.4

P (A \cap B)

P (A / B)

P (A \cup B)

P (A) = 0.8, P (B) = 0.5

P (\frac{B}{A}) = 0.4

P (A \cap B)

If P(A) = 0.8, P(B) = 0.5 and P(B|A) = 0.4, find

(i) P(A ∩ B) (ii) P(A|B) (iii) P(A ∪ B)

If P(A) = 0.5, P(B) = 0.4 and P(A $\cup$ B) = 0.8, then P(A – B) =

Join BYJU'S Learning Program