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Question

A 3.0 cm wire carryinga current of 10 A is placed inside a solenoid perpendicular to itsaxis. The magnetic field inside the solenoid is given to be 0.27 T.What is the magnetic force on the wire?

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Solution

Length of the wire, l= 3 cm = 0.03 m

Current flowing in thewire, I = 10 A

Magnetic field, B= 0.27 T

Angle between thecurrent and magnetic field, θ = 90°

Magnetic force exertedon the wire is given as:

F= BIlsinθ

=0.27 × 10 × 0.03 sin90°

=8.1 × 10–2N

Hence, the magneticforce on the wire is 8.1 × 10–2 N. Thedirection of the force can be obtained from Fleming’s left handrule.


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