Question

a 50kg man with 20 kg load on his head climbs up 20 steps of 0.25m height each. the work done in climbing is

Answer 1

Answer/Solution:

Given values:

Mass of the man = 50 Kg;
Mass of the Load = 20 Kg;
Total mass, m = 50 + 20 = 70 Kg;
Total no of steps = 20;
Height of each step = 0.25 meter;
Total height = total no. of steps x height of one step = 20 x 0.25 = 5 meter;

Hence,

Work done by the man for climbing = mgh
W = 70 x 9.8 x 5
W = 3430 Joule

Work done = 3430 J