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Byju's Answer
Standard XII
Mathematics
Formation of a Differential Equation from a General Solution
P a, b is the...
Question
P
(
a
,
b
)
is the mid-point of a line segment between axes. Show that equation of the line is
x
a
+
y
b
=
2
Open in App
Solution
Let the coordinates of
A
and
B
be
(
0
,
y
)
and
(
x
,
0
)
respectively.
Since
P
(
a
,
b
)
is the midpoint of
A
B
{
0
+
x
2
,
y
+
0
2
}
=
(
a
,
b
)
⇒
(
x
2
,
y
2
)
=
(
a
,
b
)
⇒
x
2
=
a
and
y
2
=
b
∴
x
=
2
a
and
y
=
2
b
Thus the respective coordinates of
A
and
B
are
(
0
,
2
b
)
and
(
2
a
,
0
)
The equation of the line passing through points
(
0
,
2
b
)
and
(
2
a
,
0
)
is,
⇒
(
y
−
2
b
)
=
(
0
−
2
b
)
(
2
a
−
0
)
(
x
−
0
)
⇒
y
−
2
b
=
−
2
b
2
a
(
x
)
⇒
a
(
y
−
2
b
)
=
−
b
x
⇒
a
y
−
2
a
b
=
−
b
x
⇒
b
x
+
a
y
=
2
a
b
On dividing both sides by
a
b
, we obtain
b
x
a
b
+
a
y
a
b
=
2
a
b
a
b
⇒
x
a
+
y
b
=
2
Thus equation of the line is
x
a
+
y
b
=
2
Suggest Corrections
4
Similar questions
Q.
P(a, b) is the mid point of a line segmen between axis. Show that equation of the line is
x
a
+
y
b
=
2
Q.
P ( a, b ) is the mid-point of a line segment between axes. Show that equation of the line is
Q.
The variable line
x
a
+
y
b
=
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is such that
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Q.
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x
a
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b
=
1
and
x
b
+
y
a
=
1
, meets the coordinate axes in
A
and
B
. Show that the locus of the mid point of
A
B
is the curve
2
x
y
(
a
+
b
)
=
a
b
(
x
+
y
)
Q.
If a variable straight line is drawn through the point of intersection of
x
a
+
y
b
=
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and
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Formation of a Differential Equation from a General Solution
Standard XII Mathematics
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