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Question

P(a,b) is the mid-point of a line segment between axes. Show that equation of the line is xa+yb=2

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Solution

Let the coordinates of A and B be (0,y) and (x,0) respectively.
Since P(a,b) is the midpoint of AB
{0+x2,y+02}=(a,b)
(x2,y2)=(a,b)
x2=a and y2=b
x=2a and y=2b
Thus the respective coordinates of A and B are (0,2b) and (2a,0)
The equation of the line passing through points (0,2b) and (2a,0) is,
(y2b)=(02b)(2a0)(x0)
y2b=2b2a(x)
a(y2b)=bx
ay2ab=bx
bx+ay=2ab
On dividing both sides by ab, we obtain
bxab+ayab=2abab
xa+yb=2
Thus equation of the line is xa+yb=2

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