A ball is thrown downward with an initial velocity of 10 m/sec from a height of 40 m. Find the time taken by the ball to reach the ground - [ g = 10 m/sec2]
use
s=ut+gt2/2
40=10t+10t2/2
10t+5t2-40=0
now solve this quadratic equation:
t2+2t-8=0
t2+4t-2t-8=0
t(t+4)-2(t+4)=0
(t+4)(t-2)=0
t=-4 or 2
time can not be negative so t =2