a ball is thrown upwards with velocity of 80m/s at an angle of 30 degree to the horizontal. find the velocity after 1 second.

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Solution

$I n i t i a l v e l o c i t y u = 80 m / s θ = 30^{o} i n i t i a l v e l o c i t y i n h o r i z o n t a l d i r e c t i o n u_{x} = u \cos 30 = 80 \times \frac{\sqrt{3}}{2} = 40 \sqrt{3} m / s i n i t i a l v e l c o i t y i n v e r t i c a l d i r e c t i o n u_{y} = u \sin 30 = 80 \times \frac{1}{2} = 40 m / s W e k n o w t h e r e i s n o a c c e l e r a t i o n i n h o r i z o n t a l d i r e c t i o n v_{x} = u_{x} = 40 \sqrt{3} m / s a c c e l e r a t i o n i n v e r t i c a l d i r e c t i o n i s - g v e l o c i t y a f t e r 1 s i n v e r t i c a l d i r e c t i o n i s : n e t v e l o c i t y a f t e r 1 s i s v_{y} = u_{y} - g t = 40 \sqrt{3} - 9.8 \times 1 = 59.48 m / s V = \sqrt{{V_{x}}^{2} + {V_{y}}^{2}} V = \sqrt{1600 + 3537.8} V = 71.67 m / s$

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