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Acceleration

A ball reache...

Question

A ball reaches a rocket at 60m/s along +x-direction,and leaves the rocket in the opposite direction with the same speed.Assuming that the mass of the ball as 50gm and the contact time is 0.02sec,the force exerted by the racket on the ball is

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Solution

The change in momentum of the ball, $Δ p = m v - (- m v) = 2 m v = 2 \times 0.05 \times 60 = 6 k g m / s$
Force exerted on the ball by the rocket, $F = \frac{Δ p}{Δ t} = \frac{6}{0.02} = 300 N$

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