a ball weighing 4 kg of density 4000 kg/ m3 is completely immersed in water of density 103 kg / m3.what is the force of buoyancy on it ( 10m/s2)
calculate the no. of molecules in 56g of nitrogen
If the relative density of mercury is 13.6. what's its density in si unitt
a ball weighing 4 kg of density 4000 kg/ m3 is completely immersed in water of density 103 kg / m3.what is the force of buoyancy on it ( 10m/s2)
calculate the no. of molecules in 56g of nitrogen
If the relative density of mercury is 13.6. what's its density in si unitt
Given:
Volume of the ball immersed = 4/4000 = 0.001 m3 and density of water, d = 103 kg / m3.
(1)Suppose a body of volume ‘V’ is immersed in a fluid of density ‘d’. Since, it is immersed fully the volume of fluid displaced is also equal to V. Then
The buoyant force on the body is, FB = Vdg, ‘g’ is acceleration due to gravity.
Substitute the values we can get the desired answer.
(2) Given mass = 56 g
Number of atoms can be calculated by using:
- Number of atoms = Moles * Avogadro's number
Number of moles = Given mass / molar mass
(3) If the relative density of mercury is 13.6
The relative density of a substance is the ratio of its density to that of water .
Relative density = Density of a substance / Density of water
So here in this case, Density of a mercury = 13.6 (Density of water)
Given:
Volume of the ball immersed = 4/4000 = 0.001 m3 and density of water, d = 103 kg / m3.
(1)Suppose a body of volume ‘V’ is immersed in a fluid of density ‘d’. Since, it is immersed fully the volume of fluid displaced is also equal to V. Then
The buoyant force on the body is, FB = Vdg, ‘g’ is acceleration due to gravity.
Substitute the values we can get the desired answer.
(2) Given mass = 56 g
Number of atoms can be calculated by using:
- Number of atoms = Moles * Avogadro's number
Number of moles = Given mass / molar mass
(3) If the relative density of mercury is 13.6
The relative density of a substance is the ratio of its density to that of water .
Relative density = Density of a substance / Density of water
So here in this case, Density of a mercury = 13.6 (Density of water)
