A battery of 9V is connected in series with resistors 0.2 ohm,0.3 ohm,0.4 ohm,0.5 ohm and 12 ohm respectively. How much current could flow through 12 ohm resistance ?

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Solution

For series combination,equivalent resistance will be
R=0.2 ohm+0.3 ohm+0.4 ohm+0.5 ohm +12 ohm=13.4 ohm
Now given that,V=9 V
Using Ohm's law,V=I R
I=V/R=9/13.4=0.67 A
Since same current flows in series combination,so 0.67A current will flow through 12 ohm resistance.

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A battery of 9V is connected in series with resistors 0.2 ohm,0.3 ohm,0.4 ohm,0.5 ohm and 12 ohm respectively. How much current could flow through 12 ohm resistance ?

For series combination,equivalent resistance will beR=0.2 ohm+0.3 ohm+0.4 ohm+0.5 ohm +12 ohm=13.4 ohmNow given that,V=9 VUsing Ohm's law,V=I RI=V/R=9/13.4=0.67 ASince same current flows in series combination,so 0.67A current will flow through 12 ohm resistance.

For series combination,equivalent resistance will be
R=0.2 ohm+0.3 ohm+0.4 ohm+0.5 ohm +12 ohm=13.4 ohm
Now given that,V=9 V
Using Ohm's law,V=I R
I=V/R=9/13.4=0.67 A
Since same current flows in series combination,so 0.67A current will flow through 12 ohm resistance.