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A block of ma...

Question

A block of mass 2 kg is lying on the frictionless table. A force of 8N is applied on it for 12 seconds. Calculate its Kinetic Energy.

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Solution

Given,
m=2 kg
F=8 N
t=12 sec
Using, F=ma
a=F/m=8 / 2=4 m/s²
Again,
Initial velocity of block,u=0
So, using v=u+at
v=0+ 4 x 12=48 m/s
Now,
Kinetic energy K= 1/2 mv²

^{=1/2 x 2 x 48 x 48=2304 J}

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