A body is moving in a straight line and its displacements at various instants of time are given in the following table:

Time (seconds)

0

1

2

3

4

5

6

7

Displacement (metres)

4

6

10

10

10

16

20

24
Calculate the average velocity in the time interval of 1 second to 5 second(mention the steps, too).

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Solution

Average velocity = net displacement/ total time taken.
Net displacement means distance between final and initial points.
Net displacement = 16-4 = 12 m
total time taken = 5-0 = 5 s
avg velocity = 12/5 = 2.4 m/s

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Similar questions

A body is moving in a straight line and its displacement at various instants of time is given in the following table:

$\begin{matrix} T i m e (s) & 0 & 1 & 2 & 3 & 4 & 5 & 6 & 7 D i s p l a c e m e n t (m) & 2 & 6 & 12 & 12 & 12 & 18 & 22 & 24 \end{matrix}$

Plot displacement-time graph and calculate:

(i) total distance travelled in interval 1 s to 5 s,

(ii) average velocity in time interval 1 s to 5 s.

Time (s)	0	1	2	3	4	5	6	7
Displacement (m)	2	6	12	12	12	18	22	24

Time (s)	0	1	2	3	4	5	6	7
Displacement (m)	2	6	12	12	12	18	22	24

t = 2 s

t = 5 s

m

s

A body has a displacement of 10 meters with average velocity of $5 m / s$ .Time taken is

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