a body of mass 1.5kg is attached to a linear spring which vibrates in a frequency of 2.4hz. Calculate the spring constant of the system?

Open in App

Solution

$f = 2.4 h z w = 2 π f g e t w = 15.08 r a d / s e c w = \sqrt{k / m} u s e i t t o g e t = k = 22.07 N / m$

Suggest Corrections

Similar questions

Q. A body of mass

1 k g

is made to oscillate on a spring of force constant

16 N / m .

Calculate:

1.angular frequency.

2.the frequency of vibration.

Q. Two point masses of

3 kg

and

6 kg

are attached to opposite ends of a horizontal spring, whose spring constant is

300 {Nm}^{- 1}

, as shown in the figure. The natural vibration frequency of the system is, approximately,

Q. A

1 k g

block attached to a spring vibrates with a frequency of

1 H z

on a frictionless horizontal table. Two springs identical to the original spring are attached in a parallel to an

8 k g

block placed on the same table. So, the frequency of vibration of the

8 k g

block is ;

In the given figure, a body of mass $M$ is held between two massless spring on a smooth inclined plane. The free end of the spring are attached to firm supports. If each spring has spring constant $K$ , the frequency of oscillation of the given body:

Q. A mass of 1 kg attached to the bottom of a spring has a certain frequency of vibration. The following mass has to be added to it in order to reduce the frequency by half :

Join BYJU'S Learning Program

a body of mass 1.5kg is attached to a linear spring which vibrates in a frequency of 2.4hz. Calculate the spring constant of the system?

f=2.4 hzw=2πfget w = 15.08 rad/secw= k/muse it to get = k= 22.07 N/m

$f = 2.4 h z w = 2 π f g e t w = 15.08 r a d / s e c w = \sqrt{k / m} u s e i t t o g e t = k = 22.07 N / m$