Question

a body of mass 10kg is placed on an inclined surface of an angle 30 degree . if cofficient of limiting friction is1/√3 find force required to just push the body up the inclined surfaces

Answer 1

mass = 10 kg, coefficient of limiting friction = $\frac{1}{\sqrt{3}},\theta =30°$

$$\begin{gathered} mg\cos \theta =N \\ mg\sin \theta =frictionalforce\left(f\right) \\ requiredforce=mg(\sin \theta +\mu \cos \theta ) \\ 10\times 9.8(\frac{1}{2}+\frac{1}{2})=98N \end{gathered}$$