A body of mass 2 kg is moving with a uniform speed of 30 m/s. A force of 6 N is applied against the direction of motion. How much distance will the body move in 5s after that?

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Solution

Given,
Mass of body=2 kg
Initial velocity, u=30 m/s
Time, t=5 s
Force, F=ma=-6N
or a=-6/2=-3 $m / s^{2}$
v=u+at=30-3 x 5=15 m/s
Again using,
$v^{2} - u^{2} = 2 as 15^{2} - 30^{2} = 2 \times (- 3) \times s or s = 112.5 m$

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A body of mass 2 kg is moving with a uniform speed of 30 m/s. A force of 6 N is applied against the direction of motion. How much distance will the body move in 5s after that?

Given, Mass of body=2 kg Initial velocity, u=30 m/s Time, t=5 s Force, F=ma=-6N or a=-6/2=-3 m/s2 v=u+at=30-3 x 5=15 m/s Again using, v2-u2=2as152-302=2×(-3)×sor s=112.5 m

Given,
Mass of body=2 kg
Initial velocity, u=30 m/s
Time, t=5 s
Force, F=ma=-6N
or a=-6/2=-3 $m / s^{2}$
v=u+at=30-3 x 5=15 m/s
Again using,
$v^{2} - u^{2} = 2 as 15^{2} - 30^{2} = 2 \times (- 3) \times s or s = 112.5 m$