a body of mass 60 kg is moving with a velocity of 54m/h. it is brought to rest by a force of 20N.Find the distance travelled
mass = 60kg
F = 20N
Since, F =ma
= 20 =60a
=60a =20
= a =20/60
So, a = 1/3 = 0.33 m/sec2
V = 0
u = 54m/hr
= 54/3600
= 0.015m/s
Since, v2 = u2 - 2 as(as it is retardation)
= 0 = (0.015)2-2×1/3 s
= 0.000225 -2/3 s = 0
= 2/3s = 0.000225
= s = 0.000225×3/2
= s = 0.000675/2
So, s = 0.0003375 m