A body starts to slide over a horizontal surface with an initial velocity of 0.5m/s. Due to friction, its velocity decreases at the rate of 0.05 m/s square. How much time will it take for the body to stop?

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Solution

we know that
v = u +at
here
u = 0.5
a = -0.05 m/s²
v = 0 m/s
so, time taken to stop will be
t = -u/a = -0.5/-0.05
thus,
t = 10s

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A body starts to slide over a horizontal surface with an initial velocity of 0.5m/s. Due to friction, its velocity decreases at the rate of 0.05 m/s square. How much time will it take for the body to stop?

we know thatv = u +athereu = 0.5a = -0.05 m/s2v = 0 m/sso, time taken to stop will bet = -u/a = -0.5/-0.05thus,t = 10s

we know that
v = u +at
here
u = 0.5
a = -0.05 m/s²
v = 0 m/s
so, time taken to stop will be
t = -u/a = -0.5/-0.05
thus,
t = 10s