A bomb is dropped from aeroplane when jt is at the height of 9000m. Aeroplane is moving woth velocity 400km/hr. Will the bomb hit the target at height 9000m from aeroplane?

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Solution

$I n t h e y d i r e c t i o n : 9000 m t o b e t r a v e l l e d a = 9.8 m / s^{2} 9000 = u t + 0.5 g t^{2} 9000 = 4.9 t^{2} t = 42.85 s e c I n t h e x d i r e c t i o n : 9000 m t o b e t r a v e l l e d : s p e e d = 400 k m / h r = 111.11 m / s e c s o t h e t i m e t a k e n i s = 81.0081 s e c S o i t w i l l d r o p t o t h e g r o u n d b e f o r e h i t t i n g t h e t a r g e t!$

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A bomb is dropped from aeroplane when jt is at the height of 9000m. Aeroplane is moving woth velocity 400km/hr. Will the bomb hit the target at height 9000m from aeroplane?

In the y direction:9000m to be travelleda = 9.8 m/s29000= ut + 0.5 g t29000 = 4.9t2t = 42.85 secIn the x direction:9000m to be travelled:speed = 400km/hr = 111.11 m/secso the time taken is = 81.0081 secSo it will drop to the ground before hitting the target!