A bomb of mass 9 kg explodes into pieces of masses 3 kg and 6 kg. The velocity of 3 kg
Conserving law of linear momentum:
Let v be the velocity of 6 kg mass after the explosion.
therefore 3(16) = 6(v) or v = 8 m/s
kinetic energy of the 6 kg mass = 0.5(6)(v)2= 192 Joules