a boy is running on a straight road.he runs 500 m towards north in 2 min 10 seconds and then turns back and runs 200m in 1 minute. calculate his average speed and magnitude of average velocity during first 2 minutes 10 seconds

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Solution

In the first 2min 10s the boy is travelling along a straight path. This means that distance will be equal to distance and thus average speed = average velocity.
so,
average speed = distance travelled / time taken
= 500m / 130s
thus,
average speed = average velocity = 3.85 m/s

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a boy is running on a straight road.he runs 500 m towards north in 2 min 10 seconds and then turns back and runs 200m in 1 minute. calculate his average speed and magnitude of average velocity during first 2 minutes 10 seconds

In the first 2min 10s the boy is travelling along a straight path. This means that distance will be equal to distance and thus average speed = average velocity.so,average speed = distance travelled / time taken= 500m / 130sthus,average speed = average velocity = 3.85 m/s

In the first 2min 10s the boy is travelling along a straight path. This means that distance will be equal to distance and thus average speed = average velocity.
so,
average speed = distance travelled / time taken
= 500m / 130s
thus,
average speed = average velocity = 3.85 m/s