a bullet of mass 20g moving with velocity of 200 m/s gets embedded in a freely suspended wooden target of mass 480g. calculate velocity of wooden target on being hit.

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Solution

As initial momentum = final momentum
(m1v1=m2v2)
m1=20gm, m2=(20+480=500gm)
20200=500v2
v2=4000/500
=8 m/s ANS

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a bullet of mass 20g moving with velocity of 200 m/s gets embedded in a freely suspended wooden target of mass 480g. calculate velocity of wooden target on being hit.

As initial momentum = final momentum(m1*v1=m2*v2)m1=20gm, m2=(20+480=500gm)20*200=500*v2v2=4000/500=8 m/s ANS

As initial momentum = final momentum
(m1v1=m2v2)
m1=20gm, m2=(20+480=500gm)
20200=500v2
v2=4000/500
=8 m/s ANS