A car is moving along a straight highway with a speed of 126 kmph is bought to stop within a distance of 200m. What is the distance and the tme taken to stop the car?

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Solution

Initial speed ,u = 126 km/h = 35 m/s
Distance travelled , S = 200 m
Final speed , V = 0 ( finally car stops)
Let a be the acceleration, and t be the time to stop car
$v^{2} - u^{2} = 2 a s 0 - {(35)}^{2} = 2 a (200) a = - \frac{1225}{400} = - 3.06 m / s^{2} v = u + a t 0 = 35 m / s - 3.06 m / s^{2} (t) t = 11.43 s$
time taken to stop car is 11.43 seconds
distance is 200 m

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A car is moving along a straight highway with a speed of 126 kmph is bought to stop within a distance of 200m. What is the distance and the tme taken to stop the car?

Initial speed ,u = 126 km/h = 35 m/s Distance travelled , S = 200 m Final speed , V = 0 ( finally car stops) Let a be the acceleration, and t be the time to stop car v2-u2=2as0-352=2a200a=-1225400=-3.06m/s2v=u+at0=35m/s-3.06m/s2tt=11.43s time taken to stop car is 11.43 seconds distance is 200 m